Thermal+capacity+Question+B

Assumption: No heat loss to the surroundings, i.e. all the thermal energy supplied by the heater is absorbed by the metal.

Given information: Power: P=50w Time: t=90s Mass of block: m=0.60kg Change in temperature: ΔΘ=25K

Thermal energy supplied by heater = Pt = 50 x 90 = 4500 J Thermal energy absorbed by block = mc(ΔΘ) Thermal energy supplied by heater = Thermal energy absorbed by block Pt = mc(ΔΘ) 4500 x 90 = 0.6 x c x 25
 * c = 300 J kg -1 C -1 **