Thermal+capacity+Question+F

Given information; Power = 50 W Time taken = 10 minutes = 10 x 60 = 600 seconds Mass of ethanol = 300g = 0.3 kg Mass of beaker = 60g = 0.06 kg Specific heat capacity of ethanol = 2500 J kg -1 o C -1 Specific heat capacity of glass = 650 J kg -1 o C -1 Initial temperature/ethanol = 30 o C Final temperature = T : ?

Q = Pt Q = mc(ΔΘ) 50 x 600 = 0.3 x 2500 x ( T-30 ) + 0.06 x 650 x ( T-30 ) 30000 = 789 ( T-30) 38.02 = T-30
 * T= 68.02 o C**