Thermal+capacity+Question+E

Given information: Mass of a copper block = 400g = 0.4 kg Mass of water = 200g = 0.2 kg Final temperature: 50 o C

Q = mc(ΔΘ)
Thermal energy gained by water = Thermal energy lost by copper 0.2 x 4200 x 20 = 0.4 x 400 x (//T//- 50) 16800 = 160T - 8000 160T = 24800 T = 155 o C